Product [X] formed in the above reaction is : | vedclass

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(A) The reaction proceeds in three steps:$1$. Reaction of butan$-2-$ol with $NaI$ and $H_3PO_4$ replaces the $-OH$ group with $-I$ to form $2-$iodobut

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$H_3C-CH_2-CH(D)-CH_3$

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(A) The reaction proceeds in three steps:$1$. Reaction of butan$-2-$ol with $NaI$ and $H_3PO_4$ replaces the $-OH$ group with $-I$ to form $2-$iodobutane $(CH_3-CH_2-CH(I)-CH_3)$.$2$. Reaction of $2-$iodobutane with $Mg$ in dry ether forms the Grignard reagent,sec-butylmagnesium iodide $(CH_3-CH_2-CH(MgI)-CH_3)$.$3$. The Grignard reagent reacts with $D_2O$ (deuterium oxide) to replace the $-MgI$ group with a deuterium atom,resulting in $2-$deuteriobutane $(CH_3-CH_2-CH(D)-CH_3)$.

Column-$I$ (Compound)	Column-$II$ (Major Product)
$A$. $1$-Methylcyclohexanol	$i$. $1$-Methylcyclohexene
$B$. Butan-$1$-ol	$ii$. But-$1$-ene
$C$. tert-Butyl alcohol	$iii$. Isobutylene
$D$. Butan-$2$-ol	$iv$. But-$2$-ene

Product $[X]$ formed in the above reaction is :

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