Product A is:-H-CHO xrightarrow[(ii) D_2O]{(i | vedclass

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(B) The reaction of a Grignard reagent $(R-MgBr)$ with formaldehyde $(HCHO)$ followed by hydrolysis with $D_2O$ proceeds as follows:$1$. The nucleophi

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Cyclohexylmethanol with an $-OD$ group

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(B) The reaction of a Grignard reagent $(R-MgBr)$ with formaldehyde $(HCHO)$ followed by hydrolysis with $D_2O$ proceeds as follows:$1$. The nucleophilic cyclohexyl group $(C_6H_{11}^-)$ from the Grignard reagent attacks the electrophilic carbonyl carbon of formaldehyde $(HCHO)$:$C_6H_{11}-MgBr + HCHO \rightarrow C_6H_{11}-CH_2-OMgBr$$2$. Subsequent hydrolysis with $D_2O$ replaces the $MgBr$ group with a deuterium atom $(D)$ on the oxygen,forming a deuterated alcohol:$C_6H_{11}-CH_2-OMgBr + D_2O \rightarrow C_6H_{11}-CH_2-OD + MgBr(OD)$Thus,the product $A$ is cyclohexylmethanol where the hydroxyl hydrogen is replaced by deuterium,which corresponds to the structure in option $B$.

Product $A$ is$:-$
$H-CHO \xrightarrow[(ii) D_2O]{(i) C_6H_{11}MgBr} A$

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Product $A$ is$:-$$H-CHO \xrightarrow[(ii) D_2O]{(i) C_6H_{11}MgBr} A$