The product in the given reaction is:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $LiAlH_4$ (Lithium aluminium hydride) is a strong reducing agent that reduces aldehydes,ketones,carboxylic acids,and esters to their corresponding

Vedclass · Accepted Answer

$C_6H_5-CH=CH-CH_2OH$

Vedclass · Answer

(B) $LiAlH_4$ (Lithium aluminium hydride) is a strong reducing agent that reduces aldehydes,ketones,carboxylic acids,and esters to their corresponding alcohols. However,it does not reduce isolated carbon-carbon double bonds $(C=C)$. In the given reaction,the reactant is cinnamaldehyde $(C_6H_5-CH=CH-CHO)$. $LiAlH_4$ selectively reduces the aldehyde group $(-CHO)$ to a primary alcohol group $(-CH_2OH)$ while leaving the conjugated double bond $(C=C)$ intact. Therefore,the product formed is cinnamyl alcohol,which is $C_6H_5-CH=CH-CH_2OH$.

Similar Questions

Which compound undergoes the iodoform reaction?

Acetoacetic ester behaves as

What is $C$ in the following reaction sequence?

The principal product of the reaction between methyl butanoate and $2$ moles of $CH_3MgBr$ after hydrolysis is

What will be the order of reactivity of the following carbonyl compounds with a nucleophile?
$(I)$ $HCHO$
$(II)$ $CH_3CHO$
$(III)$ $(CH_3)_2CO$
$(IV)$ $(Me_3C)_2CO$

Vedclass Test Series

Exam Paper Generator

Online Exam Module