The products obtained in the above reactions $(1)$,$(2)$,and $(3)$ are:

In the following reaction sequence, $X$ and $Z$, respectively, are:
$CH_{3}CH_{2}CH_{2}-OH + PCl_{5} \rightarrow CH_{3}CH_{2}CH_{2}Cl + X + HCl$
$CH_{3}CH_{2}CH_{2}Cl \xrightarrow{alc. KOH, \Delta} Y$
$Y \xrightarrow{HBr, (C_{6}H_{5}CO)_{2}O_{2}} Z$

Given below are four compounds:
$(a)$ $n$-propyl chloride,
$(b)$ $iso$-propyl chloride,
$(c)$ $sec$-butyl chloride,
$(d)$ $neo$-pentyl chloride.
Percentage of carbon in the one which exhibits optical isomerism is:

Match the reactions given in Column-$I$ with the types of reactions given in Column-$II$.

Match the reactions given in Column-$I$ with the names given in Column-$II$.

Given below are two statements:
Statement $I$: $C-Cl$ bond is stronger in $CH_2=CH-Cl$ than $CH_3-CH_2-Cl$.
Statement $II$: The given optically active molecule on hydrolysis gives a solution that can rotate the plane polarized light.
In the light of the above statements, choose the correct answer from the options given below.