The product $A$ obtained in the following reaction is:

An organic compound $A$ on reaction with $PCC$ $(\text{Pyridinium chlorochromate})$ gives a compound $B$. $B$ on further reaction with $I_2$ and $NaOH$ forms tri-iodomethane. Identify the compound $A$.

Among the aromatic isomers with the molecular formula $C_8H_8O$,one isomer $X$ gives the iodoform test,while another isomer $Y$ gives the Benedict's test. What are the structures of $X$ and $Y$ respectively?

You have two $C_6H_{10}O$ ketones,$I$ and $II$. Both are optically active,but $I$ is racemized by treatment with acid and $II$ is not. Wolff-Kishner reduction of both ketones gives the same achiral hydrocarbon,formula $C_6H_{12}$. What reasonable structures may be assigned to $I$ and $II$ respectively?

The product $P$ in the above reaction is

Which of the following compounds gives a yellow solid product when reacted with $NaOI$?