The product obtained when benzoyl acetic acid | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Heating a carboxylic acid with soda-lime $(NaOH + CaO)$ leads to decarboxylation,which involves the removal of a $CO_2$ molecule.Benzoyl acetic ac

Vedclass · Accepted Answer

Acetophenone

Vedclass · Answer

(A) Heating a carboxylic acid with soda-lime $(NaOH + CaO)$ leads to decarboxylation,which involves the removal of a $CO_2$ molecule.Benzoyl acetic acid is $C_6H_5-CO-CH_2-COOH$.Upon heating with soda-lime,the $-COOH$ group is removed as $Na_2CO_3$,and the hydrogen atom replaces the carboxyl group.The reaction is: $C_6H_5-CO-CH_2-COOH \xrightarrow{\Delta, NaOH/CaO} C_6H_5-CO-CH_3 + CO_2$.The product formed is Acetophenone $(C_6H_5-CO-CH_3)$.

The product obtained when benzoyl acetic acid is heated with soda-lime is:

Similar Questions

The relative reactivities of acyl compounds towards nucleophilic substitution are in the order of

An aryl carboxylic acid on treatment with sodium hydrogen carbonate liberates a gaseous molecule. Identify the gas molecule liberated.

The preferred reagent for the following conversion is $CH_3CH_2COOH \rightarrow CH_3CH_2COCl$.

Which of the following acids will form an $(a)$ anhydride on heating and $(b)$ an acid imide on strong heating with ammonia?

Vedclass Test Series

Exam Paper Generator

Online Exam Module