The product of the above Friedel-Crafts react | vedclass

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Question

(A) The reaction is an electrophilic addition of benzene to an $\alpha,\beta$-unsaturated carboxylic acid in the presence of a Lewis acid catalyst $(A

Vedclass · Accepted Answer

$3-$phenyl$-3-$methylbutanoic acid

Vedclass · Answer

(A) The reaction is an electrophilic addition of benzene to an $\alpha,\beta$-unsaturated carboxylic acid in the presence of a Lewis acid catalyst $(AlCl_3)$.$1$. The $AlCl_3$ coordinates with the carbonyl oxygen,increasing the electrophilicity of the $\beta$-carbon.$2$. This facilitates the attack of the benzene ring on the $\beta$-carbon,leading to the formation of a carbocation intermediate.$3$. The final product is $3$-phenyl-$3$-methylbutanoic acid,which corresponds to the structure shown in option $A$.

The product of the above Friedel-Crafts reaction is:

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