The product of the given reaction is:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction is an $S_NAr$ (nucleophilic aromatic substitution) reaction. The $-NO_2$ group is a strong electron-withdrawing group that activates

Vedclass · Accepted Answer

$4-$bromo$-2-$nitrophenol

Vedclass · Answer

(A) The reaction is an $S_NAr$ (nucleophilic aromatic substitution) reaction. The $-NO_2$ group is a strong electron-withdrawing group that activates the ortho and para positions towards nucleophilic attack. In $1-bromo-4-bromo-2-nitrobenzene$ (or $1,4-dibromo-2-nitrobenzene$),the bromine atom at the para position relative to the $-NO_2$ group is more susceptible to nucleophilic substitution by $HO^-$ due to the resonance stabilization of the Meisenheimer complex intermediate. Therefore,the $HO^-$ group replaces the para-bromine atom to form $4-bromo-2-nitrophenol$.

Similar Questions

Identify the product of the following Wurtz-Fittig reaction.

Arrange the following set of compounds in order of their decreasing relative reactivity with an electrophile,$E^{+}$:
$(a)$ Chlorobenzene,$2,4-$dinitrochlorobenzene,$p-$nitrochlorobenzene
$(b)$ Toluene,$p-CH_3-C_6H_4-NO_2$,$p-O_2N-C_6H_4-NO_2$

The increasing order of the rate of nucleophilic substitution reaction for the following compounds is:

Two benzyne intermediates are likely to be formed equally. Reaction with amide ion can occur in two different directions with each benzyne,giving three possible products. They are formed in a $1 : 2 : 1$ ratio. Asterisk $(*)$ refers to $^{14}C$. Product $(A)$ is:

The major products formed in the following reaction sequence are:
(Image)
$A$ and $B$ respectively are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module