The product of the reaction is:

  • A
    Meso compound
  • B
    Enantiomeric pair
  • C
    Diastereomers
  • D
    Optically pure enantiomer

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Similar Questions

Which of the following reactions are not feasible?
$I$. $CH_3CH=CH_2 \xrightarrow{HCl, (C_6H_5CO)_2O_2} CH_3CH_2CH_2Cl$
$II$. $C_6H_6 + CH_3CH_2CH_2Cl \xrightarrow{AlCl_3} C_6H_5CH(CH_3)_2$
$III$. $CH_3CHClCH_2Cl \xrightarrow{KOH, \Delta} CH_3C \equiv CH$
$IV$. $CH_3CH=CHCH_3 \xrightarrow{KMnO_4 / H^+} CH_3COOH$

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The product obtained by dry distillation of calcium formate on reacting with ammonia yields

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