Prof. Sandy Gilbert asked his students to prepare $2$-chloropropane by different methods:
Kaushal's method: $CH_3-CH(OH)-CH_3 \xrightarrow{KCl}$
Preeti's method: $CH_3-CH=CH_2 \xrightarrow{Cl_2 + H_2O}$
Raghav's method: $CH_3-CH(OH)-CH_3 \xrightarrow[Pyridine]{SOCl_2}$
Kaushal's method: $CH_3-CH(OH)-CH_3 \xrightarrow{KCl}$
Preeti's method: $CH_3-CH=CH_2 \xrightarrow{Cl_2 + H_2O}$
Raghav's method: $CH_3-CH(OH)-CH_3 \xrightarrow[Pyridine]{SOCl_2}$
- AAll three methods are correct
- BOnly Raghav's method is correct
- COnly Preeti's method is correct
- DKaushal's and Raghav's method both are correct
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View SolutionIn the following sequence of reactions,the compound $C$ formed will be:
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