Propene CH_3CH=CH_2 can be converted into pro | vedclass

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(C) The conversion of propene $(CH_3CH=CH_2)$ to propan$-1-$ol $(CH_3CH_2CH_2OH)$ is an anti-Markovnikov hydration reaction. This transformation is ac

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$B_2H_6$ and alkaline $H_2O_2$

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(C) The conversion of propene $(CH_3CH=CH_2)$ to propan$-1-$ol $(CH_3CH_2CH_2OH)$ is an anti-Markovnikov hydration reaction. This transformation is achieved via the hydroboration-oxidation process. In the first step,diborane $(B_2H_6)$ adds to the double bond,and in the second step,oxidation with alkaline hydrogen peroxide $(H_2O_2/OH^-)$ yields the primary alcohol. Therefore,the correct set of reagents is $B_2H_6$ and alkaline $H_2O_2$.

Propene $CH_3CH=CH_2$ can be converted into propan$-1-$ol by oxidation. Indicate which set of reagents amongst the following is ideal to effect the above conversion?

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