Ram is looking at his face in a mirror kept 1 | vedclass

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(C) For a concave mirror,magnification $m = \frac{f}{f-u}$. Given $m = 1.8$ and $u = -10 \ cm$ (since the object is in front of the mirror).$1.8 = \fr

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He sees a diminished and inverted image.

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(C) For a concave mirror,magnification $m = \frac{f}{f-u}$. Given $m = 1.8$ and $u = -10 \ cm$ (since the object is in front of the mirror).$1.8 = \frac{f}{f - (-10)} = \frac{f}{f + 10}$.$1.8(f + 10) = f \Rightarrow 1.8f + 18 = f \Rightarrow 0.8f = -18 \Rightarrow f = -22.5 \ cm$.Since $f$ is negative,the mirror is concave with focal length $22.5 \ cm$ and radius of curvature $R = 2f = 45 \ cm$.In the second case,the object distance $u = -50 \ cm$.Since $|u| > |R|$ (i.e.,$50 \ cm > 45 \ cm$),the object is placed beyond the center of curvature $C$.For a concave mirror,when the object is placed beyond $C$,the image formed is real,inverted,and diminished.

Ram is looking at his face in a mirror kept $10 \ cm$ away and he finds that his image is erect and magnified $(m = 1.8)$. If he holds the mirror $50 \ cm$ away,what will he see?

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