Rank the transition states that occur during | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The stability of the transition state in these $S_N1$ type dissociation steps is directly related to the stability of the resulting carbocation in

Vedclass · Accepted Answer

$1 < 3 < 2$

Vedclass · Answer

(C) The stability of the transition state in these $S_N1$ type dissociation steps is directly related to the stability of the resulting carbocation intermediate.Step $1$ produces a methyl carbocation $(CH_3^+)$,which is the least stable.Step $3$ produces an isopropyl carbocation $((CH_3)_2CH^+)$,which is a secondary $(2^o)$ carbocation.Step $2$ produces a tert-butyl carbocation $((CH_3)_3C^+)$,which is a tertiary $(3^o)$ carbocation.Since the stability order of carbocations is $3^o > 2^o > 1^o$ (methyl),the stability of the transition states follows the same order: $1 < 3 < 2$.

Rank the transition states that occur during the following reaction steps in order of increasing stability (least $\to$ most stable):
$1.$ $CH_3-O^+H_2 \to CH_3^+ + H_2O$
$2.$ $(CH_3)_3C-O^+H_2 \to (CH_3)_3C^+ + H_2O$
$3.$ $(CH_3)_2CH-O^+H_2 \to (CH_3)_2CH^+ + H_2O$

Similar Questions

Among the given pairs,in which pair does the second compound have less enol content than the first compound?

$A$ tertiary butyl carbocation is more stable than a secondary butyl carbocation because of which of the following?

Which of the following is the most stable cation?

The correct stability order of the following carbocations is:
$I$. $H_2C^+-CH=CH-CH_3$
$II$. $H_2C^+-CH=CH-BMe_2$
$III$. $H_2C^+-CH=CH-NMe_2$
$IV$. $H_2C^+-CH=CH-OMe$

$A$ species having carbon with a sextet of electrons and which can act as an electrophile is called:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Rank the transition states that occur during the following reaction steps in order of increasing stability (least $\to$ most stable):$1.$ $CH_3-O^+H_2 \to CH_3^+ + H_2O$$2.$ $(CH_3)_3C-O^+H_2 \to (CH_3)_3C^+ + H_2O$$3.$ $(CH_3)_2CH-O^+H_2 \to (CH_3)_2CH^+ + H_2O$