Rate law for a reaction between $A$ and $B$ is given by $R=k[A]^{n}[B]^{m}$. If concentration of $A$ is doubled and concentration of $B$ is halved from their initial value,the ratio of new rate of reaction to the initial rate of reaction $\left(\frac{r_2}{r_1}\right)$ is

  • A
    $2^{(n-m)}$
  • B
    $(n-m)$
  • C
    $(m+n)$
  • D
    $\frac{1}{2^{m+n}}$

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Similar Questions

The correct difference between $1^{st}$-order and $2^{nd}$-order reaction is that:

The rate law for the reaction $A + B \rightarrow C$ at $25^{\circ} C$ is given by $\text{rate} = k[A][B]^2$. Calculate the rate of reaction if the rate constant at the same temperature is $6.25 \ mol^{-2} \ dm^6 \ s^{-1}$ where $[A] = 1 \ M$ and $[B] = 0.2 \ M$.

Calculate the order of the reaction with respect to $A$ and $B$ based on the following data:
$[A] \ (mol/L)$ $[B] \ (mol/L)$ Rate $(mol/L \cdot s)$
$0.05$ $0.05$ $1.2 \times 10^{-3}$
$0.10$ $0.05$ $2.4 \times 10^{-3}$
$0.05$ $0.10$ $1.2 \times 10^{-3}$

Which one of the following statements for the order of a reaction is incorrect?

What is the time taken for the $3^{rd}$ half-life of a second-order decomposition reaction,given that its first half-life is $20 \ s$ (in $s$)?

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