The rate of reaction is maximum if G is:Cl-C_ | vedclass

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(C) The given reaction is a nucleophilic aromatic substitution reaction $(S_NAr)$.In this reaction,a nucleophile $(OH^-)$ attacks the benzene ring.Thi

Vedclass · Accepted Answer

$-NO_2$

Vedclass · Answer

(C) The given reaction is a nucleophilic aromatic substitution reaction $(S_NAr)$.In this reaction,a nucleophile $(OH^-)$ attacks the benzene ring.This process is facilitated by the presence of electron-withdrawing groups $(EWG)$ on the ring,which stabilize the intermediate carbanion (Meisenheimer complex) by dispersing the negative charge.Among the given groups,$-NO_2$ is a strong electron-withdrawing group ($-I$ and $-M$ effect),while $-OCH_3$ and $-CH_3$ are electron-donating groups.Therefore,the rate of the reaction is maximum when $G$ is $-NO_2$.

The rate of reaction is maximum if $G$ is:
$Cl-C_6H_4-G \xrightarrow{NaOH, \Delta/P} HO-C_6H_4-G$

Similar Questions

Why are aryl halides less reactive towards nucleophilic substitution reactions than alkyl halides? How can we enhance the reactivity of aryl halides?

Assertion : $S_{N}2$ reaction of an optically active aryl halide with an aqueous solution of $KOH$ always gives an alcohol with opposite sign of rotation.
Reason : $S_{N}2$ reactions always proceed with retention of configuration.

Which reaction shows the correct major product?

Predict the products for the following reaction sequence:

The weight percentage of hydrogen in $Q$,formed in the following reaction sequence,is. . . .
[Given : Atomic mass of $H = 1, C = 12, N = 14, O = 16, S = 32, Cl = 35$ ]

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The rate of reaction is maximum if $G$ is:$Cl-C_6H_4-G \xrightarrow{NaOH, \Delta/P} HO-C_6H_4-G$