Ratio of centripetal acceleration for an elec | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The centripetal acceleration is given by $a = \frac{v^2}{r}$.In Bohr's model,the velocity of an electron in the $n^{	ext{th}}$ orbit is $v \propt

Vedclass · Accepted Answer

$\frac{625}{81}$

Vedclass · Answer

(B) The centripetal acceleration is given by $a = \frac{v^2}{r}$.In Bohr's model,the velocity of an electron in the $n^{	ext{th}}$ orbit is $v \propto \frac{1}{n}$ and the radius is $r \propto n^2$.Substituting these proportionalities into the expression for acceleration,we get $a \propto \frac{(1/n)^2}{n^2} = \frac{1}{n^4}$.Therefore,the ratio of centripetal acceleration for the $3^{	ext{rd}}$ orbit $(n_1 = 3)$ and $5^{	ext{th}}$ orbit $(n_2 = 5)$ is $\frac{a_3}{a_5} = \frac{n_2^4}{n_1^4} = \frac{5^4}{3^4}$.Calculating the values,we get $\frac{625}{81}$.

Ratio of centripetal acceleration for an electron revolving in $3^{\text{rd}}$ orbit and $5^{\text{th}}$ Bohr orbit of hydrogen atom is

Similar Questions

The ratio of the radii of the second and third orbits of an $H$-atom is . . . . . . .

The time period of revolution of an electron in its ground state orbit in a hydrogen atom is $1.6 \times 10^{-16} \; s$. The frequency of revolution of the electron in its first excited state (in $s^{-1}$) is:

If the force between the electron in the first Bohr orbit and the nucleus (proton) in a hydrogen atom is $F$,then the force between them when the electron is in the second orbit is

The wavelength for an electron in an orbit of a hydrogen atom is $10^{-9} \ m$. The principal quantum number for this electron is:

Minimum excitation potential of Bohr's first orbit in hydrogen atom is.....$V$

Vedclass Test Series

Exam Paper Generator

Online Exam Module