Rationalise the denominator of the following: | vedclass

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Question

(A) To rationalise the denominator of $\frac{\sqrt{40}}{\sqrt{3}}$,we multiply both the numerator and the denominator by $\sqrt{3}$.$\frac{\sqrt{40}}{

Vedclass · Accepted Answer

$\frac{2 \sqrt{30}}{3}$

Vedclass · Answer

(A) To rationalise the denominator of $\frac{\sqrt{40}}{\sqrt{3}}$,we multiply both the numerator and the denominator by $\sqrt{3}$.$\frac{\sqrt{40}}{\sqrt{3}} = \frac{\sqrt{40} 	imes \sqrt{3}}{\sqrt{3} 	imes \sqrt{3}}$Since $\sqrt{40} = \sqrt{4 	imes 10} = 2\sqrt{10}$,we have:$= \frac{2\sqrt{10} 	imes \sqrt{3}}{3}$$= \frac{2\sqrt{30}}{3}$

Rationalise the denominator of the following: $\frac{\sqrt{40}}{\sqrt{3}}$

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