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(B) The reaction is an intramolecular aldol condensation followed by dehydration.The product is $1$-acetylcyclopentene.To form a five-membered ring vi

Vedclass · Accepted Answer

$CH_3-CO-(CH_2)_4-CHO$

Vedclass · Answer

(B) The reaction is an intramolecular aldol condensation followed by dehydration.The product is $1$-acetylcyclopentene.To form a five-membered ring via aldol condensation,the starting material must be a dicarbonyl compound with a chain length that allows the formation of a stable ring.$CH_3-CO-(CH_2)_4-CHO$ (heptane-$2,6$-dione derivative) undergoes intramolecular aldol condensation to form a five-membered ring product.Thus,the reactant $(A)$ is $CH_3-CO-(CH_2)_4-CHO$.

Reactant $(A)$ is:

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