Reaction $(A)$:
$Ph-CH=CH-CH_3 \xrightarrow[H_2O_2 / OH^-]{B_2H_6 / THF}$ products.
Reaction $(B)$:
$CH_3-CH=CH-Ph \xrightarrow[NaBH_4]{Hg(OAc)_2 / H_2O}$ products.
Correct statement is:

  • A
    In reaction $(A)$,the product is formed according to the Markownikoff rule.
  • B
    In reaction $(B)$,the product is formed according to the Antimarkownikoff rule.
  • C
    In reaction $(A)$,the product is a meso compound.
  • D
    In reaction $(B)$,the product is a racemic mixture.

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Given below are two statements: one is labelled as Assertion $(A)$ and the other is labelled as Reason $(R)$ :
Assertion $(A)$ : $S_N2$ reaction of $C_6H_5CH_2Br$ occurs more readily than the $S_N2$ reaction of $CH_3CH_2Br$.
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