The reaction between an acid and an alcohol yields:

Arrange the products $I$,$II$,$III$ from the following reactions in decreasing order of their acid strength.
$A) \text{Propylbenzene} \xrightarrow[\text{ (ii) } H_3O^{+}]{\text{ (i) } KMnO_4 / OH^{-}} I$
$B) CH_3COOH \xrightarrow[\text{ (ii) } H_2O]{\text{ (i) } Br_2 / \text{red } P} II$
$C) \text{Bromobenzene}$ $\xrightarrow[\substack{\text{ (ii) } CO_2 / \text{dry ether} \\ \text{ (iii) } H_3O^{+}}]{\text{ (i) } Mg / \text{dry ether}} III$

Acetamide reacts with $P_2O_5$ (phosphorus pentaoxide) to give:

Assertion: $CH_3COCl$ is converted to $CH_3CONH_2$ on reaction with $NH_3$.
Reason: $Cl^{-}$ is a stronger nucleophile and better leaving group.

$CH_3-CH_2-COOH$ $\xrightarrow{Br_2 / Red P} X$ $\xrightarrow{Alc. KOH / \Delta} Y$. $Y$ in the above reaction is:

$X \xrightarrow{PCl_5} C_2 H_5 Cl$
$Y \xrightarrow{PCl_5} CH_3 COCl$
$X$ and $Y$ are: