Reaction of x g of Sn with HCl quantitativel | vedclass

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(D) The chemical reaction is: $3Sn + 6HCl + C_6H_5NO_2 \rightarrow C_6H_5NH_3^+Cl^- + 3SnCl_2 + 2H_2O$.The molar mass of the organic salt (anilinium c

Vedclass · Accepted Answer

$3.57, 1.23$

Vedclass · Answer

(D) The chemical reaction is: $3Sn + 6HCl + C_6H_5NO_2 ightarrow C_6H_5NH_3^+Cl^- + 3SnCl_2 + 2H_2O$.The molar mass of the organic salt (anilinium chloride,$C_6H_5NH_3Cl$) is $129 \ g/mol$.Given that $1.29 \ g$ of the organic salt is produced,the number of moles of salt formed is $n = \frac{1.29 \ g}{129 \ g/mol} = 0.01 \ mol$.From the stoichiometry of the reaction:$1 \ mol$ of nitrobenzene produces $1 \ mol$ of organic salt.$3 \ mol$ of $Sn$ are required to produce $1 \ mol$ of organic salt.Therefore,for $0.01 \ mol$ of salt:Amount of nitrobenzene $(y)$ $= 0.01 \ mol 	imes 123 \ g/mol = 1.23 \ g$.Amount of $Sn$ $(x)$ $= 0.03 \ mol 	imes 119 \ g/mol = 3.57 \ g$.Thus,$x = 3.57$ and $y = 1.23$.

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