Reaction of an inorganic sulphite X with dilu | vedclass

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(B) The given reactions are as follows:$1$. Reaction of inorganic sulphite $X$ $(Na_{2}SO_{3})$ with dilute $H_{2}SO_{4}$:$Na_{2}SO_{3} + H_{2}SO_{4}

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$SO_{2}$ and $NaHSO_{3}$

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(B) The given reactions are as follows:$1$. Reaction of inorganic sulphite $X$ $(Na_{2}SO_{3})$ with dilute $H_{2}SO_{4}$:$Na_{2}SO_{3} + H_{2}SO_{4} \rightarrow Na_{2}SO_{4} + H_{2}O + SO_{2} (Y)$$2$. Reaction of $Y$ $(SO_{2})$ with $NaOH$:$SO_{2} + 2NaOH \rightarrow Na_{2}SO_{3} (X) + H_{2}O$$3$. Reaction of $X$ $(Na_{2}SO_{3})$ with $Y$ $(SO_{2})$ and water:$Na_{2}SO_{3} + H_{2}O + SO_{2} \rightarrow 2NaHSO_{3} (Z)$Thus,$Y$ is $SO_{2}$ and $Z$ is $NaHSO_{3}$.

Reaction of an inorganic sulphite $X$ with dilute $H_{2}SO_{4}$ generates compound $Y$. Reaction of $Y$ with $NaOH$ gives $X$. Further,the reaction of $X$ with $Y$ and water affords compound $Z$. $Y$ and $Z$,respectively,are:

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