Reaction of aniline with NaNO_{2} + dil. HCl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The correct answer is $C$ $(III)$.Step $1$: Aniline reacts with $NaNO_{2} +$ dil. $HCl$ at $0-5^{\circ} C$ to form benzene diazonium chloride $(C_

Vedclass · Accepted Answer

$III$

Vedclass · Answer

(C) The correct answer is $C$ $(III)$.Step $1$: Aniline reacts with $NaNO_{2} +$ dil. $HCl$ at $0-5^{\circ} C$ to form benzene diazonium chloride $(C_{6}H_{5}N_{2}^{+}Cl^{-})$.Step $2$: The benzene diazonium chloride then reacts with $CuCN$ (Sandmeyer reaction) to replace the diazonium group with a cyano group $(-CN)$,yielding cyanobenzene (benzonitrile) and releasing $N_{2}$ gas.Structure $III$ represents cyanobenzene.

Reaction of aniline with $NaNO_{2} +$ dil. $HCl$ at $0^{\circ} C$ followed by reaction with $CuCN$ yields:

Similar Questions

The major product in the following reaction is:

Primary nitro compounds react with $HNO_2$ to form crystalline solids which,on treatment with $NaOH$,give:

The reaction of $N,N'$-diphenylthiourea with concentrated $HCl$ upon heating is given by:
$(C_6H_5NH)_2C=S \xrightarrow{conc. HCl, Heat} A + B$
The unknown compounds $A$ and $B$ in the above reaction are:

Identify $(a)$ and $(b)$ in the following reaction:
$CH_3CH_2NH_2 + CHCl_3 + 3KOH \rightarrow (a) + (b) + 3H_2O$

The product $C$ of the following reaction sequence is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module