The reaction rate between two substances $A$ and $B$ is expressed as: $\text{rate} = k[A]^n[B]^m$. If the concentration of $A$ is doubled and the concentration of $B$ is halved,the ratio of the new rate to the initial rate will be:

  • A
    $2^{(m+n)}$
  • B
    $n-m$
  • C
    $\frac{1}{2^{(m+n)}}$
  • D
    $2^{(n-m)}$

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