Read the following two statements below carefully and state,with reasons,if it is true or false.
$(a)$ The Young's modulus of rubber is greater than that of steel;
$(b)$ The stretching of a coil is determined by its shear modulus.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) False. For a given stress,the strain produced in rubber is much larger than the strain produced in steel. Since Young's modulus $Y = \frac{\text{Stress}}{\text{Strain}}$,and $Y$ is inversely proportional to strain for a constant stress,the Young's modulus of rubber is less than that of steel.
$(b)$ True. The stretching of a coil involves a change in the shape of the wire forming the coil without changing its length significantly. This deformation is characterized by the shear modulus of the material.

Explore More

Similar Questions

If the length of a wire is reduced to half,then it can hold the ......... load.

Due to the addition of impurities,the modulus of elasticity

If the breaking force for a given wire is $F$, then the breaking force of two wires of the same material and same dimensions joined together in parallel will be

Copper has a face-centered cubic $(fcc)$ lattice with an interatomic spacing equal to $2.54 \ \mathring{A}$. The value of the lattice constant for this lattice is .... $\mathring{A}$ $[AIPMT \ 2005]$

Difficult
View Solution

Match the following:
Column-$I$ Column-$II$
$(A)$ Shear modulus $(I)$ Resistance to change in volume
$(B)$ Shearing stress $(II)$ Proportionality constant
$(C)$ Elastic fatigue $(III)$ Tangential stress
$(D)$ Modulus of elasticity $(IV)$ Temporary loss of elastic property
$(V)$ Resistance to change against deformation force

The correct match is:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo