Rearrange the following (I to IV) in the orde | vedclass

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(A) $(I)$ Mass of $1$ molecule of $O_2 = \frac{32}{6.022 	imes 10^{23}} \approx 5.31 	imes 10^{-23} \ g$$(II)$ Mass of $1$ atom of $N = \frac{14}{6.

Vedclass · Accepted Answer

$II < I < III < IV$

Vedclass · Answer

(A) $(I)$ Mass of $1$ molecule of $O_2 = \frac{32}{6.022 	imes 10^{23}} \approx 5.31 	imes 10^{-23} \ g$$(II)$ Mass of $1$ atom of $N = \frac{14}{6.022 	imes 10^{23}} \approx 2.32 	imes 10^{-23} \ g$$(III)$ $1 	imes 10^{-10} \ g$ molecular weight of $O_2 = 1 	imes 10^{-10} 	imes 32 = 3.2 	imes 10^{-9} \ g$$(IV)$ $1 	imes 10^{-10} \ g$ atomic weight of $Cu = 1 	imes 10^{-10} 	imes 63 = 6.3 	imes 10^{-9} \ g$Comparing the values: $2.32 	imes 10^{-23} Therefore,the order is $II < I < III < IV$.

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