Reductive amination of A forms :A : | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Reductive amination involves the reaction of a carbonyl compound with an amine to form an imine,which is then reduced to an amine.In the given mol

Vedclass · Accepted Answer

Vedclass · Answer

(D) Reductive amination involves the reaction of a carbonyl compound with an amine to form an imine,which is then reduced to an amine.In the given molecule $A$,there is a ketone group and a primary amine group in the same molecule.This allows for an intramolecular reductive amination.The carbonyl oxygen reacts with the primary amine group to form a cyclic imine intermediate.Reduction of this imine leads to the formation of a bicyclic amine.Specifically,the $2$-substituted cyclohexanone derivative undergoes cyclization to form a $1$-methyl$-2-$azabicyclo[$4.4$.$0$]decane or similar bicyclic structure depending on the chain length.Based on the structure of $A$,the cyclization results in the formation of the bicyclic amine shown in option $D$.

Reductive amination of $A$ forms :
$A$ :

Similar Questions

The reaction shown below proceeds via which mechanism?

The reaction sequence is as follows:
Benzene + $CH_3COCl$ $\xrightarrow{\text{Anhydrous } AlCl_3} (A)$ $\xrightarrow{(x)} \text{Ethylbenzene}$.
Reagent $(x)$ can be:

Compound $Figure$ $1$ formed by the reaction of furfural ($Figure$ $2$) with ethanol is:

The carbonyl compound that does not undergo aldol condensation is

The reaction of butanal with $n$-propylmagnesium bromide gives a

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Reductive amination of $A$ forms :$A$ :