Regarding F^{-} and Cl^{-},which of the follo | vedclass

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(A) $1$. The size of $Cl^{-}$ is larger than $F^{-}$ because $Cl$ belongs to the $3^{rd}$ period while $F$ belongs to the $2^{nd}$ period. Thus,statem

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$(i)$ and $(ii)$

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(A) $1$. The size of $Cl^{-}$ is larger than $F^{-}$ because $Cl$ belongs to the $3^{rd}$ period while $F$ belongs to the $2^{nd}$ period. Thus,statement $(iii)$ is incorrect.$2$. Since $Cl^{-}$ is larger,the valence electrons are less tightly held by the nucleus compared to $F^{-}$. Therefore,$Cl^{-}$ can lose an electron more easily than $F^{-}$. Statement $(i)$ is correct.$3$. $A$ species that loses electrons easily acts as a better reducing agent. Since $Cl^{-}$ loses electrons more easily than $F^{-}$,$Cl^{-}$ is a better reducing agent. Statement $(ii)$ is correct.$4$. Oxidation involves the loss of electrons. Since $Cl^{-}$ loses electrons more easily,it is oxidized more readily than $F^{-}$. Statement $(iv)$ is incorrect.$5$. Therefore,statements $(i)$ and $(ii)$ are correct.

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