The relation between K_1 and K_2 for the give | vedclass

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(B) The reactions represent the dissociation of cyanohydrins into carbonyl compounds and $HCN$. Reaction $(1)$ is the dissociation of acetone cyanohyd

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$K_1 > K_2$

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(B) The reactions represent the dissociation of cyanohydrins into carbonyl compounds and $HCN$. Reaction $(1)$ is the dissociation of acetone cyanohydrin,and reaction $(2)$ is the dissociation of acetaldehyde cyanohydrin. The equilibrium constant for the formation of cyanohydrin is $K_{form} = \frac{1}{K_{dissociation}}$. Aldehydes are more reactive towards nucleophilic addition than ketones due to less steric hindrance and electronic factors. Therefore,the formation constant for acetaldehyde cyanohydrin is greater than that for acetone cyanohydrin. This implies $K_{form(acetaldehyde)} > K_{form(acetone)}$. Since $K_{form} = \frac{1}{K_{dissociation}}$,we have $\frac{1}{K_2} > \frac{1}{K_1}$,which leads to $K_1 > K_2$.

The relation between $K_1$ and $K_2$ for the given equilibrium reactions is:

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