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(A) The formula for conductivity $(\kappa)$ is given by: $\kappa = G^* 	imes G$,where $G^*$ is the cell constant and $G$ is the conductance.
Conduct

Vedclass · Accepted Answer

$129$

Vedclass · Answer

(A) The formula for conductivity $(\kappa)$ is given by: $\kappa = G^* 	imes G$,where $G^*$ is the cell constant and $G$ is the conductance.
Conductance $(G)$ is the reciprocal of resistance $(R)$: $G = \frac{1}{R} = \frac{1}{100 \ \Omega} = 0.01 \ S$.
Given conductivity $\kappa = 1.29 \ S/m$.
Substituting the values into the formula: $1.29 \ S/m = G^* 	imes 0.01 \ S$.
Therefore,$G^* = \frac{1.29}{0.01} \ m^{-1} = 129 \ m^{-1}$.

Resistance of a conductivity cell filled with $0.1 \ M$ $KCl$ solution is $100 \ \Omega$ and conductivity of the solution is $1.29 \ S/m$. What will be the value of the cell constant (in $m^{-1}$)?

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