The correct order of acidic strength is:

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Question

(B) The acidic strength of carboxylic acids depends on the stability of the carboxylate anion formed after the loss of a proton. Electron-withdrawing

Vedclass · Accepted Answer

$CH_2ClCOOH > HCOOH > CH_3COOH > C_2H_5COOH$

Vedclass · Answer

(B) The acidic strength of carboxylic acids depends on the stability of the carboxylate anion formed after the loss of a proton. Electron-withdrawing groups (like $-Cl$) increase acidity by stabilizing the negative charge via the inductive effect ($-I$ effect). Electron-donating alkyl groups (like $-CH_3$,$-C_2H_5$) decrease acidity by destabilizing the negative charge via the $+I$ effect. Comparing the compounds: $1$. $CH_2ClCOOH$: The $-Cl$ atom exerts a strong $-I$ effect,making it the most acidic. $2$. $HCOOH$: No alkyl group is present,so it is more acidic than the others. $3$. $CH_3COOH$: The methyl group $(-CH_3)$ has a $+I$ effect,which is weaker than the ethyl group. $4$. $C_2H_5COOH$: The ethyl group $(-C_2H_5)$ has a stronger $+I$ effect than the methyl group,making it the least acidic. Thus,the correct order is $CH_2ClCOOH > HCOOH > CH_3COOH > C_2H_5COOH$.

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