Sarita sells a phone at a profit of 20 %. If | vedclass

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(C) Let the original cost price $(CP_1)$ of the phone be $100x$.Since she sells it at a profit of $20 \%$, the selling price $(SP_1)$ is $100x + 20x =

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$900$

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(C) Let the original cost price $(CP_1)$ of the phone be $100x$.Since she sells it at a profit of $20 \%$, the selling price $(SP_1)$ is $100x + 20x = 120x$.If she had bought it at $20 \%$ less, the new cost price $(CP_2)$ would be $100x - 20x = 80x$.She would have gained $25 \%$ on this new cost price, so the new selling price $(SP_2)$ is $80x + (25 \% 	ext{ of } 80x) = 80x + 20x = 100x$.The difference between the two selling prices is $SP_1 - SP_2 = 120x - 100x = 20x$.According to the problem, this difference is $Rs. 180$, so $20x = 180$, which means $x = 9$.The original cost price was $100x = 100 	imes 9 = Rs. 900$.

Sarita sells a phone at a profit of $20 \%$. If she had bought it at $20 \%$ less and sold it for $Rs. 180$ less, she would have gained $25 \%$. Find the cost price of the phone in $Rs.$

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