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(B) The time period $T$ of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{L}{g}}$.
Given that the time taken for $30$ oscillations i

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(B) The time period $T$ of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{L}{g}}$.
Given that the time taken for $30$ oscillations is $60 	ext{ s}$, the time period $T$ is calculated as $T = \frac{60}{30} = 2 	ext{ s}$.
Substituting the values into the formula: $2 = 2\pi \sqrt{\frac{L}{9.8}}$.
Squaring both sides of the equation, we get $4 = 4\pi^2 \frac{L}{9.8}$.
Given $\pi^2 = 9.8$, we substitute this into the equation: $4 = 4 	imes 9.8 	imes \frac{L}{9.8}$.
Simplifying the expression, we get $4 = 4L$, which gives $L = 1 	ext{ m}$.
Therefore, the correct option is $B$.

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