Schiff's reagent is used for the differentiation between:

If formaldehyde and $KOH$ are heated,then we get

In a set of reactions,an acid yielded a product $D$.
$CH_3COOH$ $\xrightarrow{SOCl_2} A$ $\xrightarrow[Anhyd. AlCl_3]{Benzene} B$ $\xrightarrow{HCN} C$ $\xrightarrow{H_3O^+} D$
Identify the product $D$.

Schiff's reagent is

Identify the product formed in the following reaction: $CH_3-CH=CH-CH_2-CHO \xrightarrow[(ii) \ H_3O^{+}]{(i) \ LiAlH_4} \text{Product}$

Given below are two statements,one is labelled as Assertion $A$ and the other is labelled as Reason $R$.
Assertion $A$: $3$-chloro-$2$-methylpentan-$3$-one can be subjected to Wolff-Kishner reduction to give $3$-chloro-$2$-methylpentane.
Reason $R$: Wolff-Kishner reduction is used to convert $C=O$ into $CH_2$.