The second ionisation potential of Li, Be, an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electronic configurations for the species formed after the first ionisation are:$Li^+: 1s^2$ (Stable noble gas configuration)$Be^+: 1s^2 2s^1$

Vedclass · Accepted Answer

$Li > B > Be$

Vedclass · Answer

(B) The electronic configurations for the species formed after the first ionisation are:$Li^+: 1s^2$ (Stable noble gas configuration)$Be^+: 1s^2 2s^1$$B^+: 1s^2 2s^2$ (Stable fully filled $2s$ subshell)To remove the second electron:For $Li^+$,we must remove an electron from the stable $1s^2$ shell,which requires very high energy.For $B^+$,we must remove an electron from the stable $2s^2$ subshell.For $Be^+$,we remove an electron from the $2s^1$ orbital,which is easier than removing from $B^+$.Therefore,the order of second ionisation potential is $Li > B > Be$.

The second ionisation potential of $Li, Be,$ and $B$ follows the order:

Similar Questions

Which of the following presents the correct order of second ionization enthalpies of $C$,$N$,$O$ and $F$?

The second ionization energy is maximum for

Ionisation energy in group $I$ elements varies in the decreasing order as:

In the photoelectric effect,if the work functions of $Li$,$Na$,and $Rb$ are $2.41 \ eV$,$2.30 \ eV$,and $2.09 \ eV$ respectively,the work function of $K$ could approximately be in $eV$?

How would you explain the fact that the first ionization enthalpy of sodium is lower than that of magnesium but its second ionization enthalpy is higher than that of magnesium?

Vedclass Test Series

Exam Paper Generator

Online Exam Module