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(D) In $[Cu(CN)_4]^{3-}$,$Cu$ is in $+1$ oxidation state ($3d^{10}$ configuration). It is colourless,tetrahedral,and diamagnetic. This is correct.In $

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$[Ni(dmg)_2] \Rightarrow 	ext{Coloured, tetrahedral, } H^{-} 	ext{ bond present}$

Vedclass · Answer

(D) In $[Cu(CN)_4]^{3-}$,$Cu$ is in $+1$ oxidation state ($3d^{10}$ configuration). It is colourless,tetrahedral,and diamagnetic. This is correct.In $[Cu(NH_3)_4]^{2+}$,$Cu$ is in $+2$ oxidation state ($3d^9$ configuration). It is coloured due to $d-d$ transition and has a square planar geometry. This is correct.In $[Pt(NH_3)_2Cl_2]$,$Pt^{2+}$ is a $5d^8$ metal ion,which forms square planar complexes. It is diamagnetic and exhibits geometrical isomerism (cis-trans). This is correct.In $[Ni(dmg)_2]$,$Ni^{2+}$ is a $3d^8$ ion. It forms a square planar complex (not tetrahedral) and is diamagnetic. It contains intramolecular hydrogen bonding. Therefore,the statement 'tetrahedral' is incorrect.

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