Select the set of quantum numbers which is NO | vedclass

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Question

(A) The electronic configuration of $Cr$ $(Z = 24)$ is $[Ar] 3d^5 4s^1$. In this configuration,the electrons are present in the $1s, 2s, 2p, 3s, 3p, 3

Vedclass · Accepted Answer

$n = 4, l = 1, m = 0, s = +\frac{1}{2}$

Vedclass · Answer

(A) The electronic configuration of $Cr$ $(Z = 24)$ is $[Ar] 3d^5 4s^1$. In this configuration,the electrons are present in the $1s, 2s, 2p, 3s, 3p, 3d,$ and $4s$ orbitals. Option $A$ corresponds to $n = 4, l = 1$,which represents a $4p$ orbital. Since there are no electrons in the $4p$ orbital for a chromium atom in its ground state,this set of quantum numbers is not associated with any electron in $Cr$.

Select the set of quantum numbers which is $NOT$ associated with any electron in $Cr$ $(Z = 24)$.

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