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(C) In the Calvin cycle of $C_3$-plants,the first stable product is $3$-phosphoglyceric acid $(3-PGA)$.During the reduction phase,$3-PGA$ is phosphory

Vedclass · Accepted Answer

First stable product of Calvin cycle undergoes phosphorylation in dark reaction

Vedclass · Answer

(C) In the Calvin cycle of $C_3$-plants,the first stable product is $3$-phosphoglyceric acid $(3-PGA)$.During the reduction phase,$3-PGA$ is phosphorylated using $ATP$ to form $1,3$-bisphosphoglycerate,which is then reduced to $3$-phosphoglyceraldehyde $(3-PGAL)$.The reaction is: $2 	imes 3-PGA + 2 ATP \longrightarrow 2 	imes 1,3-bisphosphoglycerate + 2 ADP \longrightarrow 2 	imes 3-PGAL + 2 \Pi$.Thus,the first stable product undergoes phosphorylation.

Select the correct option for photosynthesis in $C_3$-plants.

Similar Questions

Which of the following represents the Calvin cycle?

The $CO_2$ acceptor in $C_3$ plants is:

Chloroplasts contain a maximum amount of which of the following?

The path of $CO_2$ in the dark reaction of photosynthesis was successfully traced by using which of the following?

Select the incorrect option for the dark reaction.

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