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(A) Brewster's law states that $	an(i_B) = \mu_{21}$, where $\mu_{21} = \frac{\mu_2}{\mu_1}$ is the refractive index of the second medium with respec

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If the Brewster's angle for the light propagation from air to glass is $	heta$, then the Brewster's angle for the light propagating from glass to air is $(\frac{\pi}{2} - 	heta)$.

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(A) Brewster's law states that $	an(i_B) = \mu_{21}$, where $\mu_{21} = \frac{\mu_2}{\mu_1}$ is the refractive index of the second medium with respect to the first.For light propagating from air $(\mu_1 = 1)$ to glass $(\mu_2 = \mu)$, the Brewster's angle $	heta$ is given by $	an(	heta) = \frac{\mu}{1} = \mu$.For light propagating from glass $(\mu_1 = \mu)$ to air $(\mu_2 = 1)$, the Brewster's angle $i_B'$ is given by $	an(i_B') = \frac{1}{\mu}$.Since $	an(	heta) = \mu$, we have $\frac{1}{\mu} = \frac{1}{	an(	heta)} = \cot(	heta) = 	an(\frac{\pi}{2} - 	heta)$.Therefore, $i_B' = \frac{\pi}{2} - 	heta$.

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