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Question

(C) $PCl_5$: Bond pairs $(bp)$ = $5$,Lone pairs $(lp)$ = $0$. Total = $5$. Hybridization = $sp^3d$. Shape = Trigonal bipyramidal.$BrF_5$: Bond pairs $

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One of the following is square pyramidal

Vedclass · Answer

(C) $PCl_5$: Bond pairs $(bp)$ = $5$,Lone pairs $(lp)$ = $0$. Total = $5$. Hybridization = $sp^3d$. Shape = Trigonal bipyramidal.$BrF_5$: Bond pairs $(bp)$ = $5$,Lone pairs $(lp)$ = $1$. Total = $6$. Hybridization = $sp^3d^2$. Shape = Square pyramidal.$IF_7$: Bond pairs $(bp)$ = $7$,Lone pairs $(lp)$ = $0$. Total = $7$. Hybridization = $sp^3d^3$. Shape = Pentagonal bipyramidal.Thus,the correct statement is that one of the following $(BrF_5)$ is square pyramidal.

Select the correct statement regarding the shapes of $PCl_5$,$BrF_5$,and $IF_7$.

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