Select the salt whose aqueous solution is not | vedclass

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(D) The aqueous solution of $FeSO_4$ is light green due to $[Fe(H_2O)_6]^{2+}$ ions.The aqueous solution of $CrCl_3$ is green due to the formation of

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$MnCl_2$

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(D) The aqueous solution of $FeSO_4$ is light green due to $[Fe(H_2O)_6]^{2+}$ ions.The aqueous solution of $CrCl_3$ is green due to the formation of $[Cr(H_2O)_4Cl_2]^+$.The aqueous solution of $NiCl_2$ is green due to $[Ni(H_2O)_6]^{2+}$ ions.The aqueous solution of $MnCl_2$ is light pink or colourless due to $[Mn(H_2O)_6]^{2+}$ ions.Therefore,$MnCl_2$ is the salt whose aqueous solution is not green.

Column $A$	Column $B$
$(1) \ NiCl_2 \cdot 6H_2O$	$(a) \ \text{Pink}$
$(2) \ Co(NO_3)_2 \cdot 6H_2O$	$(b) \ \text{Colorless}$
$(3) \ FeCl_3$	$(c) \ \text{Blue}$
$(4) \ CuSO_4 \cdot 5H_2O$	$(d) \ \text{Green}$
	$(e) \ \text{Yellow}$

Select the salt whose aqueous solution is not green.

Similar Questions

The yellow colour solution of $Na_2CrO_4$ changes to orange-red on passing $CO_2$ gas due to the formation of

$2KMnO_4 \xrightarrow{200^{\circ}C} K_2MnO_4 + MnO_2 + O_2$. Here,'$X$' is $K_2MnO_4$. Which of the following statements is correct for '$X$'?

Match Column $A$ with Column $B$:

Column $A$ Column $B$

$(1) \ NiCl_2 \cdot 6H_2O$ $(a) \ \text{Pink}$

$(2) \ Co(NO_3)_2 \cdot 6H_2O$ $(b) \ \text{Colorless}$

$(3) \ FeCl_3$ $(c) \ \text{Blue}$

$(4) \ CuSO_4 \cdot 5H_2O$ $(d) \ \text{Green}$

$(e) \ \text{Yellow}$

Which of the following imparts green colour to the glass?

The color of acidified $K_2Cr_2O_7$ is not changed by:

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