Seven balls are drawn simultaneously from a bag containing $5$ white and $6$ green balls. The probability of drawing $3$ white and $4$ green balls is:
- A$\frac{7}{{ }^{11}C_7}$
- B$\frac{{ }^5C_3 + { }^6C_4}{{ }^{11}C_7}$
- C$\frac{{ }^5C_3 \times { }^6C_4}{{ }^{11}C_7}$
- D$\frac{{ }^6C_3 \times { }^5C_4}{{ }^{11}C_7}$
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