Shruti borrowed Rs. 2500 from her two friends | vedclass

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Question

(A) Let the amount borrowed at $8 \%$ $p.a.$ be $Rs. x$.Then,the amount borrowed at $6 \%$ $p.a.$ is $Rs. (2500 - x)$.The formula for simple interest

Vedclass · Accepted Answer

$1500$

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(A) Let the amount borrowed at $8 \%$ $p.a.$ be $Rs. x$.Then,the amount borrowed at $6 \%$ $p.a.$ is $Rs. (2500 - x)$.The formula for simple interest is $SI = \frac{P 	imes R 	imes T}{100}$.Given that the total interest for one year is $Rs. 180$,we have:$\frac{x 	imes 8 	imes 1}{100} + \frac{(2500 - x) 	imes 6 	imes 1}{100} = 180$Multiply the entire equation by $100$:$8x + 6(2500 - x) = 18000$$8x + 15000 - 6x = 18000$$2x = 18000 - 15000$$2x = 3000$$x = 1500$Therefore,the amount borrowed at $8 \%$ $p.a.$ is $Rs. 1500$.

Shruti borrowed $Rs. 2500$ from her two friends. For one loan she paid $8 \%$ $p.a.$ and for the other $6 \%$ $p.a.$ simple interest. If she paid $Rs. 180$ as total interest for one year,how much did she borrow (in $Rs.$) at $8 \%$ $p.a.?$

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