Simplified absorption spectra of three comple | vedclass

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(A) The crystal field splitting energy $(\Delta_{oh})$ is directly proportional to the strength of the ligand.The spectrochemical series for the given

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$A-(ii), B-(i), C-(iii)$

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(A) The crystal field splitting energy $(\Delta_{oh})$ is directly proportional to the strength of the ligand.The spectrochemical series for the given ligands is: $F^{-} Therefore,the order of $\Delta_{oh}$ is: $[MF_6]^{(-6+n)} Since $\Delta_{oh} = \frac{hc}{\lambda_{max}}$,the wavelength of maximum absorption $(\lambda_{max})$ is inversely proportional to $\Delta_{oh}$.Thus,the order of $\lambda_{max}$ is: $[MF_6]^{(-6+n)} > [M(NCS)_6]^{(-6+n)} > [M(NH_3)_6]^{n+}$.From the given graph,the $\lambda_{max}$ values are in the order $A Matching the values: $A$ corresponds to $[MF_6]^{(-6+n)}$ (complex $ii$),$B$ corresponds to $[M(NCS)_6]^{(-6+n)}$ (complex $i$),and $C$ corresponds to $[M(NH_3)_6]^{n+}$ (complex $iii$).Therefore,the correct match is $A-(ii), B-(i), C-(iii)$.

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