Simplify the following:frac{sqrt{24}}{8} + fr | vedclass

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(D) First,simplify the square roots:$\sqrt{24} = \sqrt{4 	imes 6} = 2 \sqrt{6}$$\sqrt{54} = \sqrt{9 	imes 6} = 3 \sqrt{6}$Substitute these into the

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$\frac{7 \sqrt{6}}{12}$

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(D) First,simplify the square roots:$\sqrt{24} = \sqrt{4 	imes 6} = 2 \sqrt{6}$$\sqrt{54} = \sqrt{9 	imes 6} = 3 \sqrt{6}$Substitute these into the expression:$\frac{2 \sqrt{6}}{8} + \frac{3 \sqrt{6}}{9} = \frac{\sqrt{6}}{4} + \frac{\sqrt{6}}{3}$Find a common denominator,which is $12$:$\frac{3 \sqrt{6}}{12} + \frac{4 \sqrt{6}}{12} = \frac{3 \sqrt{6} + 4 \sqrt{6}}{12} = \frac{7 \sqrt{6}}{12}$

Simplify the following:
$\frac{\sqrt{24}}{8} + \frac{\sqrt{54}}{9}$

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Simplify the following:$\frac{\sqrt{24}}{8} + \frac{\sqrt{54}}{9}$