Six persons A, B, C, D, E and F are standing | vedclass

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(D) $1$. Let the six persons be arranged in a circle. $2$. Given that $F$ is to the left of $D$. $3$. $A$ is between $E$ and $D$,so the sequence is $E

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$D$

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(D) $1$. Let the six persons be arranged in a circle. $2$. Given that $F$ is to the left of $D$. $3$. $A$ is between $E$ and $D$,so the sequence is $E-A-D$. $4$. $B$ is between $F$ and $C$,so the sequence is $F-B-C$. $5$. Combining these,if we place them in a circle: $D-A-E-C-B-F$ (in clockwise order). $6$. Checking the conditions: - $B$ is between $F$ and $C$ (True). - $A$ is between $E$ and $D$ (True). - $F$ is to the left of $D$ (True). $7$. Looking at the circular arrangement,the person between $A$ and $F$ is $D$ and $E$ is not the one,but looking at the sequence $D-A-E-C-B-F$,the person between $A$ and $F$ is $D$ or $E$ depending on the path. However,re-evaluating the circle: $D, A, E, C, B, F$. The person between $A$ and $F$ is $D$ and $E$ are adjacent to $A$. Wait,let's re-map: $D$ is at the top,$A$ is to its right,$E$ is to the right of $A$,$C$ is to the right of $E$,$B$ is to the right of $C$,$F$ is to the right of $B$. $8$. The sequence is $D-A-E-C-B-F$. $9$. Between $A$ and $F$ (going clockwise): $E, C, B$. Between $A$ and $F$ (going counter-clockwise): $D$. $10$. Based on standard circular seating logic,the person between $A$ and $F$ is $D$.

Six persons $A, B, C, D, E$ and $F$ are standing in a circle. $B$ is between $F$ and $C$; $A$ is between $E$ and $D$; $F$ is to the left of $D$. Who is between $A$ and $F$?

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