Sodium benzene sulphonate reacts with NaOH an | vedclass

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(A) The reaction of sodium benzene sulphonate with molten $NaOH$ followed by acidification is a standard industrial method for the preparation of phen

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Phenol

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(A) The reaction of sodium benzene sulphonate with molten $NaOH$ followed by acidification is a standard industrial method for the preparation of phenol. Step $1$: Sodium benzene sulphonate reacts with $NaOH$ to form sodium phenoxide $(C_6H_5ONa)$ and sodium sulphite $(Na_2SO_3)$. Step $2$: The resulting sodium phenoxide is then subjected to acidic hydrolysis $(H^+ / H_2O)$ to yield phenol $(C_6H_5OH)$. Therefore,the correct option is $A$.

Sodium benzene sulphonate reacts with $NaOH$ and then on acidic hydrolysis,it gives

Similar Questions

Consider the following sequence of reactions:
$C_6H_6 + CH_3CH=CH_2$ $\xrightarrow[heat]{H_3PO_4} A$ $\xrightarrow[2. H_3O^{+}, heat]{1. O_2, heat} B + C$
The products $(B)$ and $(C)$ are:

Isopropyl benzene on aerial oxidation followed by acid hydrolysis of the resulting compound yields.

Name the catalyst used in the commercial preparation of phenol.

The following equation illustrates:
$C_6H_5Cl + 2NaOH \xrightarrow{623 \ K, 300 \ atm} C_6H_5ONa + NaCl + H_2O$

Cumene on air oxidation in the presence of cobalt naphthenate forms:

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