Sodium bicarbonate $(NaHCO_3)$ has:

Which of the following statements is true with respect to $H_2O$,$NH_3$ and $CH_4$?
$A.$ The central atoms of all the molecules are $sp^3$ hybridized.
$B.$ The $H-O-H$,$H-N-H$ and $H-C-H$ angles in the above molecules are $104.5^{\circ}$,$107.5^{\circ}$ and $109.5^{\circ}$ respectively.
$C.$ The increasing order of dipole moment is $CH_4 < NH_3 < H_2O$.
$D.$ Both $H_2O$ and $NH_3$ are Lewis acids and $CH_4$ is a Lewis base.
$E.$ $A$ solution of $NH_3$ in $H_2O$ is basic. In this solution,$NH_3$ and $H_2O$ act as a Lowry-Bronsted base and acid respectively.
Choose the correct answer from the options given below:

Identify the set of molecules/ions that are isoelectronic.

Which of the following pairs have the same bond angles?
$(a) BF_3, BCl_3$
$(b) PO_4^{3-}, SO_4^{2-}$
$(c) BF_3, PF_3$
$(d) NO_2^+, N_2O$
$(e) N_3^-, NO_2$
Select the correct option:

The correct order of the $O-O$ bond length in $O_2$,$H_2O_2$,and $O_3$ is:

Assertion : The $S-S-S$ bond angle in $S_8$ molecule is $105^o$.
Reason : $S_8$ has a $V$-shape.