Solid $Ba(NO_3)_2$ is gradually dissolved in $1.0 \times 10^{-4} \, M \, Na_2CO_3$ solution. At which concentration of $Ba^{2+}$ will the precipitation begin? $(K_{sp} \, BaCO_3 = 5.1 \times 10^{-9})$
- A$4.1 \times 10^{-5} \, M$
- B$5.1 \times 10^{-5} \, M$
- C$8.1 \times 10^{-8} \, M$
- D$8.1 \times 10^{-7} \, M$
Explore More
Similar Questions
What is the molarity of $F^{-}$ in a saturated solution of $InF_3$? $(K_{sp} = 7.9 \times 10^{-10})$
Medium
View SolutionThe solubility of $A_2X_3$ is $y \ mol \ m^{-3}$. Its solubility product is equal to .......
Medium
View Solution$A$ $2.901 \ L$ saturated solution is formed by $0.08 \ g$ of $CaF_2$ at $298 \ K$. Calculate the $K_{sp}$ of $CaF_2$. (Molar mass of $CaF_2$ is $78 \ g \ mol^{-1}$)
Medium
View SolutionAssign $A$,$B$,$C$,$D$ from the given type of reaction.
$Pb(AcO)_2 + H_2S \longrightarrow PbS \downarrow + 2AcOH$
$Pb(AcO)_2 + H_2S \longrightarrow PbS \downarrow + 2AcOH$
Medium
View SolutionIf the solubility product constant $(K_{sp})$ of $Ni(OH)_2$ is $1.9 \times 10^{-15}$,the molar solubility of $Ni(OH)_2$ in $1.0 \ M \ NaOH$ is:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo