The solubility of $AgCl$ at $20 \, ^oC$ is $1.435 \times 10^{-3} \, g/L$. The solubility product $(K_{sp})$ of $AgCl$ is:

  • A
    $1.435 \times 10^{-3}$
  • B
    $1 \times 10^{-10}$
  • C
    $1.435 \times 10^{-5}$
  • D
    $108 \times 10^{-3}$

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